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180n^2=540+360n
We move all terms to the left:
180n^2-(540+360n)=0
We add all the numbers together, and all the variables
180n^2-(360n+540)=0
We get rid of parentheses
180n^2-360n-540=0
a = 180; b = -360; c = -540;
Δ = b2-4ac
Δ = -3602-4·180·(-540)
Δ = 518400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{518400}=720$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-720}{2*180}=\frac{-360}{360} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+720}{2*180}=\frac{1080}{360} =3 $
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